Question

prove that product of two consecutive positive odd integer is always odd​

Answer 1

Answer:

Step-by-step explanation:

Let the odd numbers be 2n+1, 2n+3

Now their product = (2n+1)(2n+3)

                              = $4n^{2} + 8n + 3$

                                $4n^2 + 8n + 2 + 1\\2( 2n^2 + 4n + 1) + 1\\Even No + 1\\Odd$