Question

prove that prove that the diagonals of a rectangle bisect each other and are equal by using Section formula ​

Answer 1

Explanation of the proof is as follows:

Let OABC be a rectangle such that OA is along x axis and OB is along y axis also, let OA be a and OB be b

Therefore coordinates of A are (a,0) and that of B are (b,0).

We have OABC is a rectangle.

Therefore AC = OB , i.e AC = b

Similarly,

OA = a

Therefore coordinates of Mid point of OC are (a/2, b/2) similarly mid points of AB are (a/2,b/2)

since mid points are same, therefore OC = AB

Hence Proved

Answer 2

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