Prove that q1 q2 is injective if and only if both q1 and q2 are injective.
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Step-by-step explanation:
ring of quotients of R PROOF. (i) ⇒ (ii). Now Q = E(RR) is a regular right self-injective ring. Let 1, q1, q2 ∈ Q. By Remark 1.5 there exists b∈ Q such that r · annR(b) = 0
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