Question

Prove that quadrilateral formed by intersection of interior angles of a rectangle is a rectangle(step by step)​

Answer 1

Answer:

don't know sorry shhsjshejejjd

Answer 2

ANSWER

Refer image

Given : ABCD a parallelogram

To Prove : PQRS is a rectangle

DC∣∣AB and DA is a traversal

∴∠A+∠D=180

0

2

1

∠A+

2

1

∠D=90

0

⇒∠SAD+∠SDA=90

0

∴∠ASD=90

0

∴ By concept of vertical angles

∠ASD=∠PSR=90

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Simillarly we will get

∠PQR=∠QPS=∠QRS=90

0

∴PQRS is a rectangle

solution