prove that quadrilateral trmed by the
intersection of birectors of interior anglesmade
by a transversal on two parallel lines is a
rectangle.
Answers
Answered by
0
Answer:
sorry I don't know the answer
Answered by
5
Heya mate..
l||m and p intersects them at points A and C respectively. Bisectors of interior angles intersect at B and D.
Now PAC = ACR (alternate angles)
AB||DC (as alternate angles are equal)
Similarly BC||AD
ABCD is a parallelogram
Also PAC + CAS = 180o (Linear pair)
ABCD is a ||gm with one angle 90o
ABCD is a rectangle.
HOPE IT HELPS UH ❤️
Attachments:
Similar questions