Question

Prove that (question given as attachment) ​

Answer 1

Step-by-step explanation:

hi friend,

here is your answer

LHS = 1/(seca-tana) – 1/cosa

= cosa /(1 – sina) – 1/cosa

= (cos2a – (1 – sina))/(1 – sina)(cosa)

= (sina – sin2a)/(1 – sina)(cosa)

= (sina)(1 – sina)/(1 – sina)(cosa)

= tana

RHS = 1/cosa – 1/(seca+tana)

= (1/cosa) – ( cosa/(sina+1))

= (sina +1 – cos2a)/(cosa)(sina+1)

= (sina +1 +sin2a – 1)/(sina+1)(cosa)

= sina/cosa

= tana

Hence, LHS = RHS

Hence proved.

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