prove that question please answer it fast its my hw
Attachments:
Answers
Answered by
0
Step-by-step explanation:
1+tan²A/1+cot²A=1+(sin²A/cos²A)/ 1+(cos²A/sin²A)
=(cos²A+sin²A)/cos²A÷(sin²A+cos²A)/sin²A
=cos²A/sin²A
=tan²A
(1-tanA/1-cotA)²={1-(sinA/cosA)÷ 1-(cosA/sinA)}²
=(cosA-sinA/cosA×sinA/sinA-cosA)²
={-(sinA-cosA)/cosA×sinA/(sinA-cosA)}²
=(-tanA)²
=tan²A
Attachments:
Similar questions