CBSE BOARD X, asked by sanok, 1 year ago

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Answered by Anonymous
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Answered by Anonymous
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★ Similarity of triangles should be expressed symbolically using correct correspondence of their vertices.

In ΔPQR,

∠1 = ∠2

∠PQR = ∠PRQ         [GIVEN]

∴ PR = PQ ……………..…(1)

[Sides opposite to equal angles of a triangle are also equal]

Given:

QR/QS = QT/PR

QR/QS = QT/PQ

QS/QR = PQ/QT…... …(ii) [Taking reciprocals]

[From eq  (i)]

In ΔPQS and ΔTQR,

QS/QR = PQ/QT             [From eq (ii)]

∠PQS = ∠TQR          [ common]

∴ ΔPQS ~ ΔTQR [By SAS similarity criterion]

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