Prove that radius passes through centre of the circle.
10+10 points for correct answer.
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1
Answer:
Let, O is the centre of the given circle. A tangent PR has been drawn touching the circle at point P. Draw QP ⊥ RP at point P, such that point Q lies on the circle. ... Hence, perpendicular at the point of contact to the tangent to a circle passes through the centre of the circle.
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Answer:
10 cm
Step-by-step explanation:
Length of the rope is 20 m and angle made by the rope with the ground level is 30°.
Given: AC = 20 m and angle C = 30°
To Find: Height of the pole
Let AB be the vertical pole
In right ΔABC, using sine formula
sin 30° = AB/AC
Using value of sin 30 degrees is ½, we have
1/2 = AB/20
AB = 20/2
AB = 10
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