Prove that rank of a non-Singular matrix is equal to rank of its reciprocal matrix
Answers
refer the above image....
SOLUTION
TO PROVE
The rank of a non-Singular matrix is equal to rank of its reciprocal matrix
PROOF
Let A be a non zero matrix of order m × n.
The Rank of A is defined to be the greatest positive integer r such that A has at least one non-zero minor of order r
For a non-zero m × n matrix A
0 < rank of A ≤ min {m, n}
For a non-zero matrix A of order n,
rank of A < , or = n according as A is singular or non-singular
Since the matrix A and its reciprocal matrix have the identical minors
So the rank of a non-Singular matrix is equal to rank of its reciprocal matrix
Hence proved
━━━━━━━━━━━━━━━━
Learn more from Brainly :-
The eigen values of the matrix A are 2,3,5. Then the eigen values of adj A are
https://brainly.in/question/31051731
2. let A and B are square matrices such that AB=I then zero is an eigen value of
https://brainly.in/question/24255712