Math, asked by Rajpoot6928, 1 year ago

Prove that rectangle circumscribing a circle is square

Answers

Answered by adarshcorei7
9

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this question can be solved by various ways.

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Answered by lublana
3

Answer with Step-by-step explanation:

ABCD is a rectangle

AB=CD, BC=AD

Angle A=Angle B=Angle C=Angle D=90 degrees

To prove that

AB=BC=CD=AD

Proof: AB, BC,CD and AD touch the circle at point P,Q,R and S

Tangents drawn from external point are equal.

AP=AS...(1)

PB=BQ...(2)

CR=QC..(3)

DR=DS..(4)

Adding (1), (2),(3) and (4)

Then, we get AP+PB+CR+DR=AS+BQ+QC+DS

AB+CD=AD+BC

AB+AB=BC+BC

2AB=2BC

AB=BC

When AB=CD and AB=BC

And BC=AD

Then, AB=BC=CD=AD

Hence, rectangle circumscribing a circle is a square.

#Learns more:

https://brainly.in/question/285872:Answered by NikhilMTomy

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