prove that resultant vector R = (P2 + Q2 + 2PQcos theta)^1/2
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Let two vector P and Q have same initial point and they do not meet each other .Both vector have different direction and angle between the vector is \ThetaΘ .Let a vector R which join the vector P and Q.
We can find out the value of R in terms of P ,Q and \ThetaΘ .
R^{2}=P^{2}+Q^{2}+2PQcos\ThetaR
2
=P
2
+Q
2
+2PQcosΘ
where R is the resultant vector
\sqrt{R^{2}}=\sqrt{P^{2}+Q^{2}+2PQcos\Theta
R=\sqrt{P^{2}+Q^{2}+2PQcos\Theta
here R defined only magnitude
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