Prove that rhe sum of the squares of the sides of a rohmbus is equal to the sum of the squares of its diagonals.
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1
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Let abcd a rhombus .....with centre o
Ab2=AO2+BO2
AB2=AC|2+BD|2
AB2=AC2/4+BD2/4
4Ab2=ac2+bd2
AB+BC+CD+DC=DC2+BD2
wherever I used 2 ...it mean...square ....sorry for inconvenience
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