Prove That :
Root 1 + sin Q / Root 1 - Sin Q = Tan Q + Sec Q
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Answered by
1
Answer:
Step-by-step explanation:
LHS=
1−sinA
1+sinA
=
1−sinA
1+sinA
×
1+sinA
1+sinA
=
(1+sinA)(1−sinA)
(1+sinA)
2
=
1−sin
2
A
(1+sinA)
2
=
cos
2
A
(1+sinA)
2
=
(
cosA
1+sinA
)
2
=
cosA
1+sinA
=
cosA
1
+
cosA
sinA
=secA+tanA
=RHS
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