prove that root 2 and root 5 is irrational
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HI !
To prove :-
√2 is irrational
Proof :-
Let us assume that √2 is rational
Let ,
√2 = p/q , where p and q are integers and q≠ 0 , p and q are co prime numbers.
Squaring both sides ,
2 = p²/q²
2q² = p²
2 divides p²
2 divides p ----> [1]
p = 2m
2q² = (2m)²
2q² = 4m²
q² = 2m²
2 divides q²
2 divides q ----> [2]
From 1 and 2 , 2 divides p and q .
2 is a common factor of p and q .
This is a contradiction. p and q are not co prime
Hence ,√2 is irrational.
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To prove :-
√5 is irrational
Proof :-
Let us assume that √5 is rational
Let ,
√5 = p/q , where p and q are integers and q≠ 0 , p and q are co prime numbers.
Squaring both sides ,
5 = p²/q²
5q² = p²
5 divides p²
5 divides p ----> [1]
p = 5m
5q² = (5m)²
5q² = 25m²
q² = 5m²
5 divides q²
5 divides q ----> [2]
From 1 and 2 ,
5 divides p and q .
5 is a common factor of p and q .
This is a contradiction. p and q are not co prime
Hence ,√5 is irrational.
To prove :-
√2 is irrational
Proof :-
Let us assume that √2 is rational
Let ,
√2 = p/q , where p and q are integers and q≠ 0 , p and q are co prime numbers.
Squaring both sides ,
2 = p²/q²
2q² = p²
2 divides p²
2 divides p ----> [1]
p = 2m
2q² = (2m)²
2q² = 4m²
q² = 2m²
2 divides q²
2 divides q ----> [2]
From 1 and 2 , 2 divides p and q .
2 is a common factor of p and q .
This is a contradiction. p and q are not co prime
Hence ,√2 is irrational.
===================================
To prove :-
√5 is irrational
Proof :-
Let us assume that √5 is rational
Let ,
√5 = p/q , where p and q are integers and q≠ 0 , p and q are co prime numbers.
Squaring both sides ,
5 = p²/q²
5q² = p²
5 divides p²
5 divides p ----> [1]
p = 5m
5q² = (5m)²
5q² = 25m²
q² = 5m²
5 divides q²
5 divides q ----> [2]
From 1 and 2 ,
5 divides p and q .
5 is a common factor of p and q .
This is a contradiction. p and q are not co prime
Hence ,√5 is irrational.
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