prove that root 2 is a irrational number.. with any tricky method..
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Let us assume √2 is a rational number than exists two co-prime numbers a and b Such that.
√2=a/b
√2b=a
squaring both sides
(√2b)^2=(a) ^2
2b=a^2
let a=2k (K is any integer)
2b^2=4k^2
b.^2=2k^2
Therefore our assumption was wrong
√2 is irrational number
√2=a/b
√2b=a
squaring both sides
(√2b)^2=(a) ^2
2b=a^2
let a=2k (K is any integer)
2b^2=4k^2
b.^2=2k^2
Therefore our assumption was wrong
√2 is irrational number
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