prove that root 2 is an irrational number chirkootmaths
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Your answer
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To prove : - √2 is an irrational number.
Proof : -
Let us assume √2 to be rational.
Then, there exists co-primes a and b, such that
√2 = a/b
=> (√2 )² = a²/b² [squaring both sides.]
=> 2 = a²/b²
=> a² = 2b² ......(I)
Here , 2 divides a².
So, 2 divides a.
Again,
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Let, a = 2c for some integer c.
Putting this value of a in eq.(I), we get,
(2c)² = 2b²
=> 4c² = 2b²
=> 2c² = b²
Now,
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2 divides b².
So, 2 divides b.
Thus 2 is a common factor of a and b.
But this contradicts the fact that a and b are co-primes.
This contradiction has arisen due to the incorrect assumption of √2 as rational.
∴ √2 is rational.
Hence, proved.
HOPE IT HELPS
---------------
Your answer
---------------------
To prove : - √2 is an irrational number.
Proof : -
Let us assume √2 to be rational.
Then, there exists co-primes a and b, such that
√2 = a/b
=> (√2 )² = a²/b² [squaring both sides.]
=> 2 = a²/b²
=> a² = 2b² ......(I)
Here , 2 divides a².
So, 2 divides a.
Again,
-----------
Let, a = 2c for some integer c.
Putting this value of a in eq.(I), we get,
(2c)² = 2b²
=> 4c² = 2b²
=> 2c² = b²
Now,
-------
2 divides b².
So, 2 divides b.
Thus 2 is a common factor of a and b.
But this contradicts the fact that a and b are co-primes.
This contradiction has arisen due to the incorrect assumption of √2 as rational.
∴ √2 is rational.
Hence, proved.
HOPE IT HELPS
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