prove that root 2 is irrational
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Hey mate here is your answer....
Suppose, √2 is rational.
So, take two integers a and b.
Such that, √2 = a/b and suppose a and b are co-prime.
Now, squaring on both sides.
(√2)^2 = a^2 / b^2
2 = a^2 / b^2
2b^2 = a^2................(1)
So, a is divisible by 2.
Now, suppose, a = 2k
Now, squaring on both sides.
a^2 = 4k^2...............(2)
Compare eq^n (1) & (2)
2b^2 = 4k^2.
= 4k^2 / 2b^2
b^2 = 2k^2
So, b is also divisible by 2.
But a and b are co-prime.
So, our assumption is wrong.
Therefore, √2 is irrational.
Hope it help you.... So, Plzz mark my ans as brainliest answer....
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