prove that root 2 is irrational
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1
Answer:
Let's suppose √2 is a rational number. Then we can write it √2 = a/b where a, b are whole numbers, b not zero. We additionally assume that this a/b is simplified to lowest terms, since that can obviously be done with any fraction.
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A proof that the square root of 2 is irrational.
2 = (2k)2/b2
b2 = 2k2
Step-by-step explanation:
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Answer:
Because we started the whole process assuming that a/b was simplified to lowest terms, and now it turns out that a and b both would be even. We ended at a contradiction; thus our original assumption (that √2 is rational) is not correct. Therefore √2 cannot be rational.
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A proof that the square root of 2 is irrational.
2 = (2k)2/b2
b2 = 2k2
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