prove that root 2 -root 3 as an irrational
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Answer:
To prove √2-√3
Step-by-step explanation:
- Let √2-√3 is rational number.
- √2-√3 = m ( where m is coprime number)
- √2 = m+√3
- But √2 is irrational number.
- So , our supposition is wrong.
- √2-√3 is Irrational number.
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Step-by-step explanation:
Let √2-√3 is a rational number that can be written in the form of p/q, where p and q are integers and q ≠ 0
then
√2 - √3 = p/q
√2 = p/q + √3
here ( p/q+√3 ) is an integer number that is equal to √2.
so, √2 should also be an integer number, but we know that √2 is an irrational number.
Thus,
there is an error in our assumption that's why √2 - √3 is an irrational number.
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