Math, asked by DaniyalaNikitayadav, 7 months ago

prove that root 2 -root 3 as an irrational​

Answers

Answered by kinjalrps
0

Answer:

To prove √2-√3

Step-by-step explanation:

  • Let √2-√3 is rational number.

  • √2-√3 = m ( where m is coprime number)

  • √2 = m+√3

  • But √2 is irrational number.

  • So , our supposition is wrong.

  • 2-√3 is Irrational number.

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Answered by AtqClasses
1

Step-by-step explanation:

Let √2-√3 is a rational number that can be written in the form of p/q, where p and q are integers and q ≠ 0

then

√2 - √3 = p/q

√2 = p/q + √3

here ( p/q+√3 ) is an integer number that is equal to √2.

so, √2 should also be an integer number, but we know that √2 is an irrational number.

Thus,

there is an error in our assumption that's why √2 - √3 is an irrational number.

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