prove that root 3 and root 5 are irrational number
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Let √3 be a rational no.
√3=a/b where a and b are co-prime
√3b=a
squaring
3b²=a²
3 divides a²
3 divides a
(3b) ²=3c² where c is any positive integer
9b²=3c²
3 divides c²
3 divides c
Hence it is contradiction
So, √3 is irrational
√3=a/b where a and b are co-prime
√3b=a
squaring
3b²=a²
3 divides a²
3 divides a
(3b) ²=3c² where c is any positive integer
9b²=3c²
3 divides c²
3 divides c
Hence it is contradiction
So, √3 is irrational
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