prove that root 3 is a irriatonal number through contradtion method
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let x be any rational number equal to the value of √3
now,
x=√3
x²=(√3)²
x²=3.
Here ,
x is a rational number
⇒x² is a rational no.
⇒3 is a rational no.
but 3 is a irrational no.
Here we arrive contradiction,that√3 is an irrational no.
now,
x=√3
x²=(√3)²
x²=3.
Here ,
x is a rational number
⇒x² is a rational no.
⇒3 is a rational no.
but 3 is a irrational no.
Here we arrive contradiction,that√3 is an irrational no.
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