prove that root 3 is an irrational number
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Step-by-step explanation:
root 3 consists of many non repeating numbers so root 3 is an irrational number
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Let us assume that √3 is rational.
so,
√3=a/b
√3b=a
squaring on both sides,
(√3b)^2=(a)^2
3b^2=a^2
a^2/3=b^2
Here,
3 divides a^2
so we can say that
a/3=c
a=3c
putting a=3c
kindly check the attachment 1
After attachment 1
so,
3 divides b also
Now kindly check the attachment 2
Hope it helps....
Dont forgot to see both the attachments
please make brainliest...!
Attachments:


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