prove that root 3 is irrational
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let be assume that √3 is a rational number
∴ it can be written in the form of p/q
√3 = p/q (where q ≠ 0 and p and q are
co- prime positive integers)
√3q = p
squaring both side
3q² = p² ⇒ (1)
p² is divisible by 3
∴ p is also divisible by 3
∴ 3c = p
squaring both side
9c² = p² ⇒ (2)
from (1) and (2)
9c² = 3q²
3c² = q²
q² is divisible by 3
∴ q is also divisible by 3
therefore, 3 is a common factor of p and q
but it is contradict that p and q are co prime
positive integers
∴ our assumption is wrong and √3 is an irrational
number
hence proved
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