Prove that root 3 is irrational.
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Let us assume that √3 is irrational
let, √3=a/b. {where a and b are integers and b≠0}
=>3=a²/b²
=>a²=3b²
a² is divisible by 3
a is also divisible by 3
Again,
Let a=3c
=>a²=(3c²) {squaring both side}
=>3b²=6c²
=>b²=3c²
b² is divisible by 3
b is also divisible by 3
Therefore ,both a and b have common factor of 3
So, This contradict the fact that our assumption is incorrect
Therefore, √3 is irrational
let, √3=a/b. {where a and b are integers and b≠0}
=>3=a²/b²
=>a²=3b²
a² is divisible by 3
a is also divisible by 3
Again,
Let a=3c
=>a²=(3c²) {squaring both side}
=>3b²=6c²
=>b²=3c²
b² is divisible by 3
b is also divisible by 3
Therefore ,both a and b have common factor of 3
So, This contradict the fact that our assumption is incorrect
Therefore, √3 is irrational
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