Math, asked by ciugvyvhcx, 1 year ago

Prove that root 3 is irrational

Answers

Answered by keerthika6
6

Let us assume that √3 is a rational number.


then, as we know a rational number should be in the form of p/q


where p and q are co- prime number.


So,


√3 = p/q { where p and q are co- prime}


√3q = p


Now, by squaring both the side


we get,


(√3q)² = p²


3q² = p² ........ ( i )



So,


if 3 is the factor of p²


then, 3 is also a factor of p ..... ( ii )



=> Let p = 3m { where m is any integer }


squaring both sides


p² = (3m)²


p² = 9m²


putting the value of p² in equation ( i )


3q² = p²


3q² = 9m²


q² = 3m²


So,


if 3 is factor of q²


then, 3 is also factor of q



Since


3 is factor of p & q both


So, our assumption that p & q are co- prime is wrong


Read more on Brainly.in - https://brainly.in/question/2346612#readmore

Answered by Arshad2003
1

It cannot be expressed in p/ q form .. that’s why..

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