prove that root 3 is irrationally
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LET US TAKE √3 AS RATIONAL
SO,√3=P/Q
a/b,WHERE A AND B ARE COMPOSITE NUMBERS
NOW,
a/b=√3
so,a=b√3
squaring both sides
a×a=b×b×3
so ,3 divides a×a
=3 also divides a
let a=c×3
then,(3c)=b×b×3
9c=b×b×3
3c=b×b
so, 3 divides b×b
also 3 divides b
But it is not possible as a and b are COMPOSITE NUMBERS
So our assumption is incorrect
i.e√3is irrational
mark as brailiest if it helps
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