prove that root 3 - root 2 is a irrational number
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√3-√2 =p/q (q is not equal to 0)
(√3-√2) ²=(p/q) ²
3+2-2√6=p²/q²
5-2√6=p²/q²
2√6=5-p²/q²
√6=5q²-p²/2q²
this assumes that 5q²-p²/2q² is rational so as √6
but √6 is not rational hence this contradicts our assumption... so √3-√2 is irrational
(√3-√2) ²=(p/q) ²
3+2-2√6=p²/q²
5-2√6=p²/q²
2√6=5-p²/q²
√6=5q²-p²/2q²
this assumes that 5q²-p²/2q² is rational so as √6
but √6 is not rational hence this contradicts our assumption... so √3-√2 is irrational
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