Math, asked by annapoornaxdor, 1 year ago

prove that root 3 + root 2 is irrational given that root 6 is irrational ​

Answers

Answered by Anonymous
30

Let √2 + √3 = (a/b) is a rational no. On squaring both sides , we get 2 + 3 + 2√6 = (a2/b2) So,5 + 2√6 = (a2/b2) a rational no. So, 2√6 = (a2/b2) – 5 Since, 2√6 is an irrational no. and (a2/b2) – 5 is a rational no. So, my contradiction is wrong. So, (√2 + √3) is an irrational no.


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Answered by balav1301
1

Answer:

please explain

Step-by-step explanation:

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