prove that root 3+root 5 is irrational
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let as assume root as rational
so it has co-prime numbers a&b
root 3 = a/b
(squaring on both sides)
3=a square/ b square
* a square = 3b square (*)
: 3/a square & 3/a - (1)
a =3c
(square on both sides)
a square = 9c square
apply (*)
3b square = 9c square
b square = 9c square / 3
= 3c square
: b/3 square& b/3 -(2)
in the view of (1) &(2)
we can say our assumption is wrong because both 1 & 2 has 3 as common factors.
therefore root 3 is irrational.
now let as assume root5 as rational
so it has co-prime numbers a&b
root 5 = a/b
(squaring on both sides)
5=a square/ b square
* a square = 5b square (*)
: 5/a square & 5/a - (1)
a =5c
(square on both sides)
a square = 25c square
apply (*)
5b square = 25c square
b square = 25c square / 5
= 5c square
: b/5 square& b/5 -(2)
in the view of (1) &(2)
we can say our assumption is wrong because both 1 & 2 has 5 as common factors.
therefore root 5 is irrational.
so the root 3 + root 5 is irrational
hence proved
it helps u so plzz mrk as brainlist
so it has co-prime numbers a&b
root 3 = a/b
(squaring on both sides)
3=a square/ b square
* a square = 3b square (*)
: 3/a square & 3/a - (1)
a =3c
(square on both sides)
a square = 9c square
apply (*)
3b square = 9c square
b square = 9c square / 3
= 3c square
: b/3 square& b/3 -(2)
in the view of (1) &(2)
we can say our assumption is wrong because both 1 & 2 has 3 as common factors.
therefore root 3 is irrational.
now let as assume root5 as rational
so it has co-prime numbers a&b
root 5 = a/b
(squaring on both sides)
5=a square/ b square
* a square = 5b square (*)
: 5/a square & 5/a - (1)
a =5c
(square on both sides)
a square = 25c square
apply (*)
5b square = 25c square
b square = 25c square / 5
= 5c square
: b/5 square& b/5 -(2)
in the view of (1) &(2)
we can say our assumption is wrong because both 1 & 2 has 5 as common factors.
therefore root 5 is irrational.
so the root 3 + root 5 is irrational
hence proved
it helps u so plzz mrk as brainlist
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