Prove that root 3 + root 5 is irrational number by contadiction method only
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Iamabarbiegirl:
Thank u but it is root 3 + root 5
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Let us suppose 3+root 5 is rational.
=>3+root 5 is in the form of p/q where p and q are integers and qis not =0
=>root5=p/q-3
=>root 5=p-3q/q
as p, q and 3 are integers p-3q/3 is a rational number.
=>root 5 is a rational number
but we know that root 5 is an irrational number.this is an contradiction.
This contradiction has arisen because of our wrong assumption that 3+root 5 is a rational number .
Hence 3+ root 5 is an irrational number.
=>3+root 5 is in the form of p/q where p and q are integers and qis not =0
=>root5=p/q-3
=>root 5=p-3q/q
as p, q and 3 are integers p-3q/3 is a rational number.
=>root 5 is a rational number
but we know that root 5 is an irrational number.this is an contradiction.
This contradiction has arisen because of our wrong assumption that 3+root 5 is a rational number .
Hence 3+ root 5 is an irrational number.
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