prove that root 3 + root 7 is an irrational number by contradiction
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Answered by
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Step-by-step explanation:
A rational number can be written in the form of p/q where 'p' and 'q' are co-prime rational integers and q≠0. Then, √3 + √7 = p/q. ... Thus proved that √3+√7 is irrational.
Answered by
0
Answer:
We have to prove that 3+
7
is irrational.
Let us assume the opposite, that 3+
7
is rational.
Hence 3+
7
can be written in the form
b
a
where a and b are co-prime and b
=0
Hence 3+
7
=
b
a
⇒
7
=
b
a
−3
⇒
7
=
b
a−3b
where
7
is irrational and
b
a−3b
is rational.
Since,rational
= irrational.
This is a contradiction.
∴ Our assumption is incorrect.
Hence 3+
7
is irrational.
Hence proved.
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