prove that root 3is irrational number
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let √3 be a rational number
√3 =a/b,where A and B are co primes and b is not equal to zero .
(by cross multiplication )
a=√3b
SBS
a square =√3b whole square
a square = 3 b square
root 3 is a factor of a and a square
a=3c
SBS
a square=3b square
9c square= 3b square
( here we cancel out 9 by 3 )
3c square = b square
under root 3 is a factor of b square and b
hence √3 is a factor of both a and b . but A and B are co primes hands as the position is wrong the √3 is an irrational number
√3 =a/b,where A and B are co primes and b is not equal to zero .
(by cross multiplication )
a=√3b
SBS
a square =√3b whole square
a square = 3 b square
root 3 is a factor of a and a square
a=3c
SBS
a square=3b square
9c square= 3b square
( here we cancel out 9 by 3 )
3c square = b square
under root 3 is a factor of b square and b
hence √3 is a factor of both a and b . but A and B are co primes hands as the position is wrong the √3 is an irrational number
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