Prove that root 5 -3 root 2 is irrational. It should be root 5 not 5
Answers
Answer: hi mate here is ur answer
Step-by-step explanation:
step 1 - let us assume √5 is a rational no.
we know that rational nos can be written as p/q
so ,√5 can be written as p/q(where p,q are co-prime )
⇒ √5 =p/q (eq -1)
step 2- square on both sides (eq-1)
⇒5 = p²/q²
⇒5q²= p²
⇒q²= p²/5 (here 5 divides p² that means it also divides p) (eq-2)
step 3 - for 5 dividing p let there be some no called r
⇒p/5= r (sq. on both sides)
⇒ p²/25 = r²(from eq -2 substitute the value of p ²)
⇒5q²/25 = r²
⇒q²/5 = r²
here 5 divides q ² so it also divides q but this is a contradiction to our statement .
hence √5 is irrational
we know that any irrational no. subtracted from any no. gives the result as irrational. so , √5 -√3-2 is an irrational no.
hence proved
hope it helps !!!