prove that root 5 ia an irrationa number
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Answer:
by the method of contradiction .
let us assume that √5 is rational number .
so,
√5 = a÷ b
b√5=a
squaring on both sides
a² = 5b² ---------------------------------------------------------- ( 1 )
if 5 divides a then 5 also divides b
a = 5c
squaring on both sides
a²=25c² -----------------------------------------------------------( 2 )
substitute equation 1 in equation 2
5b²=25c²
b²=5c²
here a,b,c have 5 as common factor
so,
5 is rational number
but √5 is irrational
this contradiction has arrisen due to our incorrect assumption
this contadicts the fact that ,
√5 is irrational
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