prove that root 5 is a irrational number
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Answered by
6
Hello dear♥
here is ur answer☺☺
Let us assume that √5 is a rational number.
we know that the rational numbers are in the form of p/q form where p,q are intezers.
so, √5 = p/q
p = √5q
we know that 'p' is a rational number. so √5 q must be rational since it equals to p
but it doesnt occurs with √5 since its not an intezer
therefore, p =/= √5q
this contradicts the fact that √5 is an irrational number
hence our assumption is wrong and √5 is an irrational number.
Thankyou☺☺☺
♥♥♥♥♥♥♥♥
here is ur answer☺☺
Let us assume that √5 is a rational number.
we know that the rational numbers are in the form of p/q form where p,q are intezers.
so, √5 = p/q
p = √5q
we know that 'p' is a rational number. so √5 q must be rational since it equals to p
but it doesnt occurs with √5 since its not an intezer
therefore, p =/= √5q
this contradicts the fact that √5 is an irrational number
hence our assumption is wrong and √5 is an irrational number.
Thankyou☺☺☺
♥♥♥♥♥♥♥♥
Answered by
1
Answer:
lets us assume on the contrary that root 5 is a rational number then there exist coprime positive integers a and b such that
Step-by-step explanation:
hence root 5 is irrational
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