prove that root 5 is an irrational number
Answers
Answer:
Prove that root 5 is irrational number
Given: √5
We need to prove that √5 is irrational
Proof:
Let us assume that √5 is a rational number.
Sp it t can be expressed in the form p/q where p,q are co-prime integers and q≠0
⇒√5=p/q
On squaring both the sides we get,
⇒5=p²/q²
⇒5q²=p² —————–(i)
p²/5= q²
So 5 divides p
p is a multiple of 5
⇒p=5m
⇒p²=25m² ————-(ii)
From equations (i) and (ii), we get,
5q²=25m²
⇒q²=5m²
⇒q² is a multiple of 5
⇒q is a multiple of 5
Hence, p,q have a common factor 5. This contradicts our assumption that they are co-primes. Therefore, p/q is not a rational number
√5 is an irrational number
Answer:
let be assume that √5 is a rational no.
∴ it can be written in the form of a/b
√5 = a/b (where a and b are co prime
positive integers b ≠ 0)
√5b = a
squaring both side
5b² = a² ⇒ (1)
a² is divisible by 5
∴ a is also divisible by 5
5c = a
squaring both side
25c² = a² ⇒ (2)
from (1) and (2)
25c² = 5b²
5c² = b²
b² is divisible by 5
∴ b is also divisible by 5
∴ 5 is a common factor of a and b
but it is contradict that a and b are
co prime therefore our assumption
is wrong and √5 is an irrational no.
HENCE PROVED
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