Prove that root 5 is irrational.
subham322669:
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Answered by
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because root 5 is neither terminating nor repeaing
Answered by
4
Step-by-step explanation:
Let √5 as rational number.
So we can write it in the form of p/q.
where p and q are co primes and q ≠ 0.
Now squaring both sides.
√5 ^2 = ( p/ q)^2
5 = p^2/q^2
p^2 = 5q^2
p^2/5 = q^2
If p^2 is divisible by 5 .
Then p can also be divisible by 5.
So p is any multiple of 5
So let 5c = p
Now squaring both sides.
25c ^2 = p^2
putting value of p^2.
25 c^2 = 5 q^2
5 c^2 = q^2
c ^2 = q^2/5.
If q^2 is divisible by 5 then q is also divisible by 5 .
So q is also a multiple of 5.
P and Q have a common factor 5 other than 1 . So these are not co prime.
Our hypothesis was wrong
√5 is irrational number.
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