prove that root 5 is irrational and also give that statement
Answers
5 is the common factor of p and q,
tfore out assumption was wrong
tfore root 5 is irrational
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Let us assume to contrary that √5 is rational number.
i.e., we can find a and b(≠0) such two positove coprime integers so that,
a/b = √5
a = √5b
squaring both sides,
a² = 5b² -(1)
now,
a²/5 = b²
clearly a² is divisible by 5
it means a is also divisible by 5
so,
a is divisible by 5 -(2)
we can find any integer q such that,
a = 5q
squaring both sides,
a² = 25q²-(3)
from (1) and (3),
25q² = 5b²
5q² = b²
b²/5 = q²
clearly,
b² is divisible by 5
it means,
b is divisible by 5-(4)
from (2) and (4),
a and b both are divisible by 5
it means a and b atleast must have 5 as common factor,
But, this contradicts the fact that a and b are co prime integers.
This contradiction has arisen due to our incorrect assumption that √5 is rational.
So, we conclude that √5 is irrational.