prove that root 5 is irrational
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Answered by
1
Step-by-step explanation:
let root 5 is rational
then√5=p/q
p=q√5
squaring on both sides
p^2=q^2*5
q^2=p^2/5
so 5 divides p square and also p
let p=5m
now 5^2*m^2/5=q^2
now msquare=q square by5
5divides q square and also q
so 5 is prime
but this contradicts √5 is irrational
so √5is irrational
Answered by
1
Answer:
Let ✓5 be a rational number.
Then it can be written as √5=a/b
✓5b=a
now, squaring both sides
(✓5b)²=a²
5b²=a²
a² is divisible by 5.
a is also divisible by 5.
now,
5b²=(5m)² (let m be any integer)
5b²=25m²
b²=5m
b² is divisible by 5
b is also divisible by 5.
hence,
a and b have common factor 5 other than 1.
this contradiction has arisen because of our wrong assumption.
Therefore, ✓5 is irrational.
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