prove that root 5 is irrational , hence 3+2root5 is irrational
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Answered by
1
irrational numbers refer to incompleting numbers
√5 = 2.236............goes on
which is an irrational numbers. ..
3+ 2√5 = 3 + 2(2.236........)
=3+4.472.........
=7.472............. .
which is an irrational numbers
hope this helps you
pls mark my answer as brainliest answer
√5 = 2.236............goes on
which is an irrational numbers. ..
3+ 2√5 = 3 + 2(2.236........)
=3+4.472.........
=7.472............. .
which is an irrational numbers
hope this helps you
pls mark my answer as brainliest answer
Answered by
5
Answer :
Given that, √5 is irrational.
Let us consider that (3 + 2√5) is rational and
3 + 2√5 = a/b, where a and b are integers with non-zero b.
⇒ 2√5 = a/b - 3
⇒ 2√5 = (a - 3b)/b
⇒ √5 = (a - 3b)/2b
Since, both a and b are integers (a - 3b) and 2b are also integers and thus (a - 3b)/2b be rational number.
But √5 being irrational, a contradiction is shown.
Thus, (3 + 2√5) is irrational. [Proved]
#MarkAsBrainliest
Given that, √5 is irrational.
Let us consider that (3 + 2√5) is rational and
3 + 2√5 = a/b, where a and b are integers with non-zero b.
⇒ 2√5 = a/b - 3
⇒ 2√5 = (a - 3b)/b
⇒ √5 = (a - 3b)/2b
Since, both a and b are integers (a - 3b) and 2b are also integers and thus (a - 3b)/2b be rational number.
But √5 being irrational, a contradiction is shown.
Thus, (3 + 2√5) is irrational. [Proved]
#MarkAsBrainliest
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