Prove that root 5 + roo 7 is irrational no
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let us assume that root 7 and root 5 are rational
then root 7 +root 5 = a/b where a and b are co primes
then square on both sides
(root 7 +root 5)square = a /bwhole square
2xroot 35= a/b whole square -12
root 35 = 1/2(a/b whole square -12)
RHS is rational
but root 35 is irrational as root 7 and root 7 are irrational
this contradiction has arisen due to our incorrect assumption
thus root 7 +root 5 is irrational
hence the proof
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then root 7 +root 5 = a/b where a and b are co primes
then square on both sides
(root 7 +root 5)square = a /bwhole square
2xroot 35= a/b whole square -12
root 35 = 1/2(a/b whole square -12)
RHS is rational
but root 35 is irrational as root 7 and root 7 are irrational
this contradiction has arisen due to our incorrect assumption
thus root 7 +root 5 is irrational
hence the proof
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3
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LET 5+ROOT 7=RATIONAL NUMBER
5+ROOT 7=P/Q, WHERE P AND Q ARE some integer and q is not equal to zero...
5+root 7=p/q
Root 7=p/q-5
Root 7=p-5q/q
Here irrational number is equal to rational number which is never be possible
so our assumption is wrong that 5+root7 is rational number
Therefore 5+root7 is a irrational number.
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5+ROOT 7=P/Q, WHERE P AND Q ARE some integer and q is not equal to zero...
5+root 7=p/q
Root 7=p/q-5
Root 7=p-5q/q
Here irrational number is equal to rational number which is never be possible
so our assumption is wrong that 5+root7 is rational number
Therefore 5+root7 is a irrational number.
@mohitkingj
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