Prove that root 5 - root 2 is an irrational number
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Answer:
Step-by-step explanation:
So
First assume that ✓5 is a rational number
Therefore
✓5 =p\q (where p and q are integers and co prime numbers and q not equal to 0)
Then squaring both side
(✓5)^2 =p^2\q^2
5 = p^2\q^2
q^2= p^2\5 ( if p square is divisible by 5 then p is also divisible by 5)
Then, Take p =5m
q^2= (5m)^2\5
q^2= 25m^2\5
25 will be canceld by 5 and it becomes
= 5m^2\q^2 (if q square is divisible by 5 then q is also divisible by 5)
Therefore, we assumed √5 as a co prime no but is is not.....
So our assumption was wrong
=> √5 Is an irrational numbers
And as we know the sum of irrational and irrational numbers gives an irrational numbers
Therefore √5 -√2 is an irrational numbers
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