prove that root 5 + root 3 is not a rational number
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Assume that √3 + √5 = p/q (it's rational).
Multiple both sides by (√5 - √3).
(√5 - √3) (√5 + √3) = 5-3 = 2 = p/q * (√5 - √3)
(√5 - √3) = 2q/p, therefore √5 - √3 is rational = 2q/p
√5 + √3 = p/q
√5 - √3 = 2q/p
√5 = [(p/q) + (2q/p)]/2, a rational number.
But we know that √5 is IRRATIONAL (easily provable, let me know if you need the proof).
Therefore the assumption is wrong and √3 + √5 is irrational.
Multiple both sides by (√5 - √3).
(√5 - √3) (√5 + √3) = 5-3 = 2 = p/q * (√5 - √3)
(√5 - √3) = 2q/p, therefore √5 - √3 is rational = 2q/p
√5 + √3 = p/q
√5 - √3 = 2q/p
√5 = [(p/q) + (2q/p)]/2, a rational number.
But we know that √5 is IRRATIONAL (easily provable, let me know if you need the proof).
Therefore the assumption is wrong and √3 + √5 is irrational.
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