Prove that root 5is irrational
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let us suppose that √5 is an rational no. it can be represented in the form of p/q where p & q are co prime no.
√5=p/q
on squaring both sides
5=p^2/q^2
5q^2=p^2............1
p^2/5 so p/5
p =5r
on s.b.s
p^2=25r^2
from eq. 1
5q^2=25r^2
q^2=5r^2
q^2/5&q/5
here p&q are divisible by 5 so it contradicts our assumption
hence √5 is an irrational no.....
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