Question

prove that root 5is irrational ​

Answer 1

Step-by-step explanation:

Let us assume that √5 is a rational number.

we know that the rational numbers are in the form of p/q form where p,q are intezers.

so, √5 = p/q

p = √5q

we know that 'p' is a rational number. so √5 q must be rational since it equals to p

but it doesnt occurs with √5 since its not an intezer

therefore, p =/= √5q

this contradicts the fact that √5 is an irrational number

hence our assumption is wrong and √5 is an irrational number.

hope it helped u :)

Answer 2

Answer:

==> √5 is an irrational..

Step-by-step explanation:

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Let us assume that √5 is a rational number.

we know that the rational numbers are in the form of p/q form where p,q are intezers.so, √5 = p/q

==> p = √5q

p = √5qwe know that 'p' is a rational number. so √5 q must be rational since it equals to pbut it doesnt occurs with √5 since its not an intezertherefore, p =/= √5qthis contradicts the fact that √5 is an irrational number....

hence our assumption is wrong and √5 is an irrational number.

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$\huge\mathbb\red{Rishik}$