prove that root 6 + root 2 is irrational number
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Step-by-step explanation:
- let us first assume √6+√2 is a rational number
- therefore, it can be written as p/q, assuming p and q are co prime where q=/=0
- so, √6+√2 = p/q
- squaring on both sides,
6+2√12+2 = p/q
(putting all rational numbers in RHS)
√3= p/4q - 8
LHS is irrational while RHS is rational. This contradiction has occurred due to it incorrect assumption that √6+√2 is rational
therefore, √6+√2 is irrational.
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Step-by-step explanation:
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