prove that root 7 is irrational
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let root 7is a rational number were p and q are some integers q not =0
let a and b are the simplest form of p and q . these are Co-prime having only 1 factor.
√7=a/b
squaring on both sides
7=a sqo and b sqo
or
7b sq= a sq (i)
7 divide a sq
7 divide a also or theroeom 1.3
let a/7=c
then a=7c
squaring on both sides we get
a sq. 49c sq. (2)
c sq =49/a sq
a sq divide 49
put the a sq in
equation (1)
7b sq = 49 c sq
7 divide b sq
so, there a and b have at least 7 common factor other than 1.
This contradiction has arisen because of our incorrect assumption. √7 is a irrational.
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