Prove that root 7 is irrational
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It cannot be expressed in p/ q form ... that’s why...
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HEY BUDDY HERE IS UR ANSWER !!
Let root 7 be rational number
root7 = p/q
[p and q be co-prime number , where q is not equal to 0 ]
(root 7)^2 = (p/q)^2 [squaring both the sides ]
7 = p^2/q^2
7/q^2 =p^2 --- (1)
p^2 divides 7
p divides 7
now let p^2 = 7p
put value in eq (1)
7/q^2 = (7p)^2
7/q^2 = 49 p^2
q^2 = 49p^2 / 7
q^2 = 7 p^2
q^2 divides 7
q divides 7
Hence ,our contradiction is wrong
root 7 is irrational number .
Hope u like my process !
》》 BE BRAINLY 《《
Let root 7 be rational number
root7 = p/q
[p and q be co-prime number , where q is not equal to 0 ]
(root 7)^2 = (p/q)^2 [squaring both the sides ]
7 = p^2/q^2
7/q^2 =p^2 --- (1)
p^2 divides 7
p divides 7
now let p^2 = 7p
put value in eq (1)
7/q^2 = (7p)^2
7/q^2 = 49 p^2
q^2 = 49p^2 / 7
q^2 = 7 p^2
q^2 divides 7
q divides 7
Hence ,our contradiction is wrong
root 7 is irrational number .
Hope u like my process !
》》 BE BRAINLY 《《
Sweetbuddy:
mark my answer as brainalist one
I liked ur process
hmmm
plz tag my answer as brainalist one
I can’t do
because it was not me who asked this question
ik
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