Prove that root 7 root 5 is an irrational
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Answered by
5
Answer:
Let 7√5 be a rational number.
So,
7√5 = p/q.
(p and q are co-prime number and q ≠ 0)
=> √5 = p/7q
As, we can see that p/7q ia rational so √5 should also be rational. But this contradict the fact that √5 is irrational.
So, by this we can say that 7√5 is irrational number.
Hope this helps...:)
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Step-by-step explanation:
Answered by
1
Answer:
Let 7√5 be a ratoonal number number so; (p and q are co - prime numvber 5 and q. is not = to 0) = √5=p/q As we can see that p/7q is rational number -r .But this contaradict the fact the √5 is. irriational so; by this we can say that 7√5 i. is irrational number. # hope it helps
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