Math, asked by tharakeshwars3, 8 months ago

Prove that root 7 root 5 is an irrational​

Answers

Answered by Anonymous
5

Answer:

Let 7√5 be a rational number.

So,

7√5 = p/q.

(p and q are co-prime number and q ≠ 0)

=> √5 = p/7q

As, we can see that p/7q ia rational so √5 should also be rational. But this contradict the fact that √5 is irrational.

So, by this we can say that 7√5 is irrational number.

Hope this helps...:)

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Step-by-step explanation:

Answered by ranjanakarup
1

Answer:

Let 7√5 be a ratoonal number number so; (p and q are co - prime numvber 5 and q. is not = to 0) = √5=p/q As we can see that p/7q is rational number -r .But this contaradict the fact the √5 is. irriational so; by this we can say that 7√5 i. is irrational number. # hope it helps

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